| From: | To: |
The formula to calculate Joules (J) from Voltage (V) and Charge (C) is:
\[ E (\text{J}) = V (\text{V}) \times Q (\text{C}) \]
Where:
Volt (V) is a unit of electric potential, representing the potential difference between two points. Joule (J) is a unit of energy, representing the amount of work done when a force of one newton displaces a mass by one meter. The conversion from volts to joules depends on the charge flowing through the circuit.
Let's assume the following values:
Using the formula:
\[ E = 12 \times 5 \]
\[ E = 60 \text{ J} \]
The Energy (J) is 60 J.
| Voltage (V) | Charge (C) | Energy (J) |
|---|---|---|
| 10 | 5 | 50.000 |
| 20 | 5 | 100.000 |
| 30 | 5 | 150.000 |
| 40 | 5 | 200.000 |
| 50 | 5 | 250.000 |
| 60 | 5 | 300.000 |
| 70 | 5 | 350.000 |
| 80 | 5 | 400.000 |
| 90 | 5 | 450.000 |
| 100 | 5 | 500.000 |
| 110 | 5 | 550.000 |
| 120 | 5 | 600.000 |
| 130 | 5 | 650.000 |
| 140 | 5 | 700.000 |
| 150 | 5 | 750.000 |
| 160 | 5 | 800.000 |
| 170 | 5 | 850.000 |
| 180 | 5 | 900.000 |
| 190 | 5 | 950.000 |
| 200 | 5 | 1,000.000 |
| 210 | 5 | 1,050.000 |
| 220 | 5 | 1,100.000 |
| 230 | 5 | 1,150.000 |
| 240 | 5 | 1,200.000 |
| 250 | 5 | 1,250.000 |
| 260 | 5 | 1,300.000 |
| 270 | 5 | 1,350.000 |
| 280 | 5 | 1,400.000 |
| 290 | 5 | 1,450.000 |
| 300 | 5 | 1,500.000 |
| 310 | 5 | 1,550.000 |
| 320 | 5 | 1,600.000 |
| 330 | 5 | 1,650.000 |
| 340 | 5 | 1,700.000 |
| 350 | 5 | 1,750.000 |
| 360 | 5 | 1,800.000 |
| 370 | 5 | 1,850.000 |
| 380 | 5 | 1,900.000 |
| 390 | 5 | 1,950.000 |
| 400 | 5 | 2,000.000 |
| 410 | 5 | 2,050.000 |
| 420 | 5 | 2,100.000 |
| 430 | 5 | 2,150.000 |
| 440 | 5 | 2,200.000 |
| 450 | 5 | 2,250.000 |
| 460 | 5 | 2,300.000 |
| 470 | 5 | 2,350.000 |
| 480 | 5 | 2,400.000 |
| 490 | 5 | 2,450.000 |
| 500 | 5 | 2,500.000 |