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The formula to calculate Kilowatt-Hours (kWh) from Power (W) and Time (hours) is:
\[ E (\text{kWh}) = \frac{P (\text{W}) \times t (\text{hours})}{1000} \]
Where:
Watt (W) is a unit of power, representing the rate of energy usage per time unit. Kilowatt-Hour (kWh) is a unit of energy, representing the amount of energy used over a period of time. The conversion from watts to kilowatt-hours depends on the time over which the power is applied.
Let's assume the following values:
Using the formula:
\[ E = \frac{1500 \times 2.5}{1000} \]
\[ E = 3.75 \text{ kWh} \]
The Energy (kWh) is 3.75 kWh.
| Power (W) | Time (hours) | Energy (kWh) |
|---|---|---|
| 100 | 5 | 0.500 |
| 200 | 5 | 1.000 |
| 300 | 5 | 1.500 |
| 400 | 5 | 2.000 |
| 500 | 5 | 2.500 |
| 600 | 5 | 3.000 |
| 700 | 5 | 3.500 |
| 800 | 5 | 4.000 |
| 900 | 5 | 4.500 |
| 1000 | 5 | 5.000 |
| 1100 | 5 | 5.500 |
| 1200 | 5 | 6.000 |
| 1300 | 5 | 6.500 |
| 1400 | 5 | 7.000 |
| 1500 | 5 | 7.500 |
| 1600 | 5 | 8.000 |
| 1700 | 5 | 8.500 |
| 1800 | 5 | 9.000 |
| 1900 | 5 | 9.500 |
| 2000 | 5 | 10.000 |
| 2100 | 5 | 10.500 |
| 2200 | 5 | 11.000 |
| 2300 | 5 | 11.500 |
| 2400 | 5 | 12.000 |
| 2500 | 5 | 12.500 |
| 2600 | 5 | 13.000 |
| 2700 | 5 | 13.500 |
| 2800 | 5 | 14.000 |
| 2900 | 5 | 14.500 |
| 3000 | 5 | 15.000 |
| 3100 | 5 | 15.500 |
| 3200 | 5 | 16.000 |
| 3300 | 5 | 16.500 |
| 3400 | 5 | 17.000 |
| 3500 | 5 | 17.500 |
| 3600 | 5 | 18.000 |
| 3700 | 5 | 18.500 |
| 3800 | 5 | 19.000 |
| 3900 | 5 | 19.500 |
| 4000 | 5 | 20.000 |
| 4100 | 5 | 20.500 |
| 4200 | 5 | 21.000 |
| 4300 | 5 | 21.500 |
| 4400 | 5 | 22.000 |
| 4500 | 5 | 22.500 |
| 4600 | 5 | 23.000 |
| 4700 | 5 | 23.500 |
| 4800 | 5 | 24.000 |
| 4900 | 5 | 24.500 |
| 5000 | 5 | 25.000 |