| From: | To: |
The formula to calculate Volts (V) from Power (W) and Current (A) is:
For DC:
\[ V (\text{V}) = \frac{P (\text{W})}{I (\text{A})} \]
For Single Phase AC:
\[ V (\text{V}) = \frac{P (\text{W})}{I (\text{A})} \]
For Three Phase AC:
\[ V (\text{V}) = \frac{P (\text{W})}{I (\text{A}) \times \sqrt{3}} \]
Where:
Watt (W) is a unit of power, representing the rate of energy usage per time unit. Volt (V) is a unit of electric potential, representing the potential difference between two points. The conversion from watts to volts depends on the current and the phase of the circuit.
Let's assume the following values:
Using the formula for Single Phase AC:
\[ V = \frac{1000}{5} \]
\[ V = 200 \text{ V} \]
The Voltage (V) is 200 V.
| Power (W) | Current (A) | Voltage (V) |
|---|---|---|
| 200 | 10 | 11.547 |
| 400 | 10 | 23.094 |
| 600 | 10 | 34.641 |
| 800 | 10 | 46.188 |
| 1000 | 10 | 57.735 |
| 1200 | 10 | 69.282 |
| 1400 | 10 | 80.829 |
| 1600 | 10 | 92.376 |
| 1800 | 10 | 103.923 |
| 2000 | 10 | 115.470 |
| 2200 | 10 | 127.017 |
| 2400 | 10 | 138.564 |
| 2600 | 10 | 150.111 |
| 2800 | 10 | 161.658 |
| 3000 | 10 | 173.205 |
| 3200 | 10 | 184.752 |
| 3400 | 10 | 196.299 |
| 3600 | 10 | 207.846 |
| 3800 | 10 | 219.393 |
| 4000 | 10 | 230.940 |
| 4200 | 10 | 242.487 |
| 4400 | 10 | 254.034 |
| 4600 | 10 | 265.581 |
| 4800 | 10 | 277.128 |
| 5000 | 10 | 288.675 |